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IBM ILE RPG Programmer Sample Questions:
1. Given the following code sample:
DName+++++++++++ETDsFrom+++To/L+++IDc.Keywords+++++++++++++++++++++++ D
StudentDS E DS Extname(Students)
Which of the following keywords should be added to the D-spec to initialize subfields to the
defaults specified in the DDS?
A) inz(*File)
B) inz(*Flddft)
C) inz(*Extdft)
D) inz(*ExtDDS)
2. Given the following H-spec:
h datedit(*mdy)
Which of the following conditions tests whether a job started prior to midnight and is still running
after midnight?
A) if %date(udate:*mdy) < %date();
B) ifudate < %date();
C) if %date(*date:*mdy) < %date();
D) if *date < %date();
3. Which of the following is an advantage gained by using %kds instead of a KLIST?
A) The ability to test for an equal match on a SETLL operation
B) The ability to use a varying number of keys
C) The ability to use date fields as keys
D) The ability to use array elements as keys
4. Given the following code sample: FFilename++IPEASF.....L.....
A) DName+++++++++++ETDsFrom+++To/L+++IDc.Keywords++++++++++++
d MyCustomer ds extname(custrec)
B) DName+++++++++++ETDsFrom+++To/L+++IDc.Keywords++++++++++++
d MyCustomer e ds likerec(customer)
C) DName+++++++++++ETDsFrom+++To/L+++IDc.Keywords++++++++++++ d MyCustomer e ds extname(customer)
D) DName+++++++++++ETDsFrom+++To/L+++IDc.Keywords++++++++++++
d MyCustomer ds likerec(custrec)
E) Device+.Keywords++++++++++++++++++++
fcustomer if e k disk rename(customer:custrec)
Which of the following data specifications produces a qualified data structure with subfields
matching the layout of file CUSTOMER?
5. File CUSSALES contains a field named JANSALES. Work fields SALESKEY and TOTSALES have been previously defined. Given the following fixed form code sample: ..CL0N01Factor1+++++++Opcode(E)+Factor2+++++++Result++++++++Len++D+HiLoEq c z-add customerno saleskey 7575 c 75saleskey chain cussales 76 c 75 cann76 add jansales totsales Which of the following /Free form samples would produce the same results for field TOTSALES?
A) saleskey = customerno;
if customerno <> 0;
chain saleskey cussales;
if %equal(cussales);
totsales += jansales;
endif;
B) ifcustomerno <> 0;
saleskey = customerno;
chain saleskey cussales;
if not %found(cussales);
totsales += jansales;
endif;
C) ifcustomerno <> 0;
saleskey = customerno;
chain saleskey cussales;
if %found;
totsales += jansales;
endif;
D) saleskey = customerno;
if saleskey > 0;
chain saleskey cussales;
if %equal(cussales);
totsales += jansales;
endif;
Solutions:
| Question # 1 Answer: C | Question # 2 Answer: A | Question # 3 Answer: B | Question # 4 Answer: A | Question # 5 Answer: C |






