IBM Fundamentals of Quantum Computation Using Qiskit v0.2X Developer : C1000-112

C1000-112 pass collection

Exam Code: C1000-112

Exam Name: Fundamentals of Quantum Computation Using Qiskit v0.2X Developer

Updated: May 30, 2026

Q & A: 250 Questions and Answers

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IBM Fundamentals of Quantum Computation Using Qiskit v0.2X Developer Sample Questions:

1. What is the role of Qiskit Aer in the Qiskit framework?

A) Providing quantum algorithmic solutions
B) Offering simulators for quantum circuits and backends for real hardware
C) Visualizing quantum circuits and their gates
D) Implementing quantum error correction codes


2. Which of the following statements best describes the role of Qasm in programming quantum circuits?

A) Qasm provides a way to visualize quantum circuit execution
B) Qasm is a programming language used for quantum hardware communication
C) Qasm describes classical computations that support quantum circuits
D) Qasm describes the sequence of quantum operations in a circuit


3. Assuming the fragment below, which three code fragments would produce the circuit illustrated?
inp_reg = QuantumRegister(2, name='inp')
ancilla = QuantumRegister(1, name='anc')
qc = QuantumCircuit(inp_reg, ancilla)
# Insert code here

A) qc.h(inp_reg[1])
qc.h(inp_reg[2])
qc.x(ancilla[1])
qc.draw()
B) qc.h(inp_reg[0:1])
qc.x(ancilla[0])
qc.draw()
C) qc.h(inp_reg[0:2])
qc.x(ancilla[0])
qc.draw()
D) qc.h(inp_reg[0])
qc.h(inp_reg[1])
qc.x(ancilla[0])
qc.draw()
E) qc.h(inp_reg)
qc.x(ancilla)
qc.draw()
F) qc.h(inp_reg) qc.h(inp_reg) qc.x(ancilla) qc.draw()


4. Which two code fragments, when inserted into the code below, will produce the statevector shown in the output?
from qiskit import QuantumCircuit, Aer, execute
from math import sqrt
qc = QuantumCircuit(2)
# Insert fragment here
simulator = Aer.get_backend('statevector_simulator')
result = execute(qc, simulator).result()
statevector = result.get_statevector()
print(statevector)
Output:
[0.707+0.j 0.+0.j 0.+0.j 0.707+0.j]

A) v = [1/sqrt(2), 0, 0, 1/sqrt(2)]
qc.initialize(v,[0,1])
B) qc.h(0)
qc.h(1)
qc.measure_all()
C) qc.cx(0,1)
qc.measure_all()
D) v1, v2 = [1,0], [0,1]
qc.initialize(v1,0)
qc.initialize(v2,1)
E) qc.h(0)
qc.cx(0,1)


5. Which two options would place a barrier across all qubits to the QuantumCircuit below?
qc = QuantumCircuit(3,3)

A) qc.barrier()
B) qc.barrier_all()
C) qc.barrier([0,1,2])
D) qc.barrier(3)
E) qc.barrier(qc)


Solutions:

Question # 1
Answer: B
Question # 2
Answer: D
Question # 3
Answer: C,D,E
Question # 4
Answer: A,E
Question # 5
Answer: A,C

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