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Oracle Introduction to Oracle9i: SQL Sample Questions:

1. Examine the structures of the EMPLOYEES and TAX tables.

You need to find the percentage tax applicable for each employee. Which SQL statement would you use?

A) You cannot find the information because there is no common column between the two tables.
B) SELECT employee_id, salary, tax_percent FROM employees e, tax t WHERE MIN(e.salary) = t.min_salary AND MAX(e.salary) = t.max_salary
C) SELECT employee_id, salary, tax_percent FROM employees e, tax t WHERE e.salary > t.min_salary, tax_percent
D) SELECT employee_id, salary, tax_percent FROM employees e, tax t WHERE e.salary BETWEEN t.min_salary AND t.max_salary;

2. Evaluate the set of SQL statements:
CREATE TABLE dept (deptno NUMBER(2), dname VARCHAR2(14), loc VARCHAR2(13)); ROLLBACK; DESCRIBE DEPT
What is true about the set?

A) The DESCRIBE DEPT statement displays the structure of the DEPT table only if there is a COMMIT statement introduced before the ROLLBACK statement.
B) The ROLLBACK statement frees the storage space occupies by the DEPT table.
C) The DESCRIBE DEPT statement returns an error ORA-04043: object DEPT does not exist.
D) The DESCRIBE DEPT statement displays the structure of the DEPT table.

3. The EMPLOYEE tables have these columns:

You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column.
Which SQL statement displays the desired results?

A) SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;
B) SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;
C) SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;
D) SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;

4. A subquery can be used to _________.

A) Convert data to a different format
B) Sort data in a specific order
C) Create groups of data
D) Retrieve data based on an unknown condition

5. EMPLOYEES and DEPARTMENTS data:

On the EMPLOYEES table, EMPLOYEE_ID is the primary key. MGR_ID is the ID
managers and refers to the EMPLOYEE_ID.
On the DEPARTMENTS table DEPARTMENT_ID is the primary key.
Evaluate this UPDATE statement.
UPDATE employees
SET mgr_id =
(SELECT mgr_id
FROM employees
WHERE dept_id=
(SELECT department_id
FROM departments
WHERE department_name = 'Administration')),
Salary = (SELECT salary
FROM employees
WHERE emp_name = 'Smith')
WHERE job_id = 'IT_ADMIN';
What happens when the statement is executed?

A) The statement executes successfully, leaves the manager ID as the existing value, and changes the salary to 4000 for the employees with ID 103 and 105.
B) The statement fails because there is more than one row matching the IT_ADMIN job ID in the EMPLOYEES table.
C) The statement fails because there is no 'Administration' department in the DEPARTMENTS table.
D) The statement fails because there is more than one row matching the employee name Smith.
E) The statement executes successfully, changes the manager ID to NULL, and changes the salary to 4000 for the employees with ID 103 and 105.
F) The statement executes successfully, changes the manager ID to NULL, and changes the salary to 3000 for the employees with ID 103 and 105.

Solutions: